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E needs algebra help again
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<blockquote data-quote="TeDo" data-source="post: 550344"><p>To find the y intercept you need to put a 0 (zero) in for x and solve. In this case y= 0^2 - 14(0)-51 or y = -51. To find the x intercepts, you have to make the y a zero and solve. To do that you need to find all the factors of 51 (1,3,17,51). Since the two signs are both negative, the larger factor must be negative and the smaller one is positive because when they are multiplied, they need to be negative and when added, then also need to be negative. Here's what I got.</p><p></p><p>0=k^2 - 14k - 51</p><p>0= (k-17)(k+3)</p><p></p><p>Then you set each one equal to zero and solve like this:</p><p></p><p> 0=k-17 and 0=k+3</p><p>17=k and -3=k</p><p></p><p>The y intercept is (0, -51) and the x intercepts are (17,0) and (-3, 0).</p><p></p><p>Does that make sense?? I really hate doing the work FOR kids but since you had the answers but didn't understand the process, the only way to explain the process is to show it.</p></blockquote><p></p>
[QUOTE="TeDo, post: 550344"] To find the y intercept you need to put a 0 (zero) in for x and solve. In this case y= 0^2 - 14(0)-51 or y = -51. To find the x intercepts, you have to make the y a zero and solve. To do that you need to find all the factors of 51 (1,3,17,51). Since the two signs are both negative, the larger factor must be negative and the smaller one is positive because when they are multiplied, they need to be negative and when added, then also need to be negative. Here's what I got. 0=k^2 - 14k - 51 0= (k-17)(k+3) Then you set each one equal to zero and solve like this: 0=k-17 and 0=k+3 17=k and -3=k The y intercept is (0, -51) and the x intercepts are (17,0) and (-3, 0). Does that make sense?? I really hate doing the work FOR kids but since you had the answers but didn't understand the process, the only way to explain the process is to show it. [/QUOTE]
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E needs algebra help again
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