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Any math people here??? -- *updated*
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<blockquote data-quote="Kathy813" data-source="post: 42890" data-attributes="member: 1967"><p>Hey Sheila,</p><p></p><p>I'm good for something!</p><p></p><p>smallworld's kids are exactly right. Here is how to think it through:</p><p></p><p>In the first problem, the events are independent of each other. In other words, the probability of the second event occuring is not altered by the first event. Since you want to roll a 1,2,3 on the first roll (3 favorable outcomes out of 6 possible outcomes) which is 3/6 or 1/2 "and" you want to roll a 4,5,6 on the second roll (3 favorable outcomes out of 6) which is 3/6 or 1/2, you multiply the probabilities together and 1/2 times 1/2 is 1/4 or a 25% probability.</p><p></p><p>Now, in the second problem, once you pick a penny the same penny cannot be picked again to the second probiblity is dependent on the first. So you have to approach it a little differently.</p><p></p><p>The first probability is 4 pennies out of 9 coins which is a 4/9 probability. The second probability is 3 remaining pennies out of 8 remaining coins or 3/8. Again, you multiply the probabilities together so 4/9 times 3/8 is a 1/6 chance or a 16.7% probability.</p><p></p><p>Way to go, smallworld's math whiz kids!! :bravo:</p><p></p><p>~Kathy</p></blockquote><p></p>
[QUOTE="Kathy813, post: 42890, member: 1967"] Hey Sheila, I'm good for something! smallworld's kids are exactly right. Here is how to think it through: In the first problem, the events are independent of each other. In other words, the probability of the second event occuring is not altered by the first event. Since you want to roll a 1,2,3 on the first roll (3 favorable outcomes out of 6 possible outcomes) which is 3/6 or 1/2 "and" you want to roll a 4,5,6 on the second roll (3 favorable outcomes out of 6) which is 3/6 or 1/2, you multiply the probabilities together and 1/2 times 1/2 is 1/4 or a 25% probability. Now, in the second problem, once you pick a penny the same penny cannot be picked again to the second probiblity is dependent on the first. So you have to approach it a little differently. The first probability is 4 pennies out of 9 coins which is a 4/9 probability. The second probability is 3 remaining pennies out of 8 remaining coins or 3/8. Again, you multiply the probabilities together so 4/9 times 3/8 is a 1/6 chance or a 16.7% probability. Way to go, smallworld's math whiz kids!! [img]:bravo:[/img] ~Kathy [/QUOTE]
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Any math people here??? -- *updated*
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